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利用sql脚本检查测验数据表中一列数据是还是不

主题素材根源:近年来有同事须求实践批量刨除语句。依据他提供的政工必要,推荐他使用“TRUNCATE TABLE”语句。但使用该语句需求 ALTE奥迪Q5权限,那与试行顾客的角色不符。

SQL数据库面试题以及答案

Student(Sno,Sname,Sage,Ssex) 学生表       Sno:学号;Sname:学生姓名;Sage:学生年龄;Ssex:学生性别
Course(Cno,Cname,Tno) 课程表                    Cno,课程编号;Cname:课程名字;Tno:教授编号
SC(Sno,Cno,score) 战绩表                             Sno:学号;Cno,课程编号;score:战绩
Teacher(Tno,Tname) 教师表                        Tno:教授编号; Tname:教授名字

 

创设数据表:

create table Student(

Sno varchar(10) not null primary key,

Sname varchar(20) null,

Sage int null,

Ssex varchar(2) null

)

create table Course(

Cno varchar(10) not null primary key,

Cname varchar(20) null,

Tno varchar(20) null

)

create table SC(

Sno varchar(10) not null primary key,

Cno varchar(10) not null primary key,

score int null

)

create table Teacher(

Tno varchar(20) primary key not null,

Tname varchar(20) null

)

问题:
1、查询“001”课程比“002”课程成绩高的富有学员的学号;
  select a.Sno from (select Sno,score from SC where Cno='001') a,(select Sno,score
  from SC where Cno='002') b
  where a.score>b.score and a.Sno=b.Sno;
2、查询平均成绩超乎60分的同校的学号和平均战表;
    select Sno,avg(score)
    from sc
    group by Sno having avg(score) >60;
3、查询全部同学的学号、姓名、选课数、总战表;
  select Student.Sno,Student.Sname,count(SC.Cno),sum(score)
  from Student left Outer join SC on Student.Sno=SC.Sno
  group by Student.Sno,Sname
4、查询姓“李”的大校的个数;
  select count(distinct(Tname))
  from Teacher
  where Tname like '李%';
5、查询没学过“叶平”老师课的同学的学号、姓名;
    select Student.Sno,Student.Sname
    from Student 
    where Sno not in (select distinct( SC.Sno) from SC,Course,Teacher where SC.Cno=Course.Cno and Teacher.Tno=Course.Tno  and Teacher.Tname='叶平');
6、查询学过“001”而且也学过数码“002”课程的同桌的学号、姓名;
  select Student.Sno,Student.Sname from Student,SC where Student.Sno=SC.Sno and SC.Cno='001'and exists( Select * from SC as SC_2 where SC_2.Sno=SC.Sno and SC_2.Cno='002');
7、查询学过“叶平”老师所教的全部课的同窗的学号、姓名;
  select Sno,Sname
  from Student
  where Sno in (select Sno from SC ,Course ,Teacher where SC.Cno=Course.Cno and Teacher.Tno=Course.Tno and Teacher.Tname='叶平' group by Sno having count(SC.Cno)=(select count(Cno) from Course,Teacher  where Teacher.Tno=Course.Tno and Tname='叶平'));
8、查询课程编号“002”的大成比课程编号“001”课程低的具有同学的学号、姓名;
  Select Sno,Sname from (select Student.Sno,Student.Sname,score ,(select score from SC SC_2 where SC_2.Sno=Student.Sno and SC_2.Cno='002') score2
  from Student,SC where Student.Sno=SC.Sno and Cno='001') S_2 where score2 <score;
9、查询全数科目战表小于60分的同班的学号、姓名;
  select Sno,Sname
  from Student
  where Sno not in (select Student.Sno from Student,SC where S.Sno=SC.Sno and score>60);
10、查询未有学全全部课的同校的学号、姓名;
    select Student.Sno,Student.Sname
    from Student,SC
    where Student.Sno=SC.Sno group by  Student.Sno,Student.Sname having count(Cno) <(select count(Cno) from Course);

11、查询最少有一门课与学号为“1001”的同班所学同样的校友的学号和姓名;
    select Sno,Sname from Student,SC where Student.Sno=SC.Sno and Cno in select Cno from SC where Sno='1001';
12、查询起码学过学号为“001”同学全数一门课的其余同学学号和姓名;
    select distinct SC.Sno,Sname
    from Student,SC
    where Student.Sno=SC.Sno and Cno in (select Cno from SC where Sno='001');
13、把“SC”表中“叶平”老师教的课的战绩都改成为此课程的平均成绩;
    update SC set score=(select avg(SC_2.score)
    from SC SC_2
    where SC_2.Cno=SC.Cno ) from Course,Teacher where Course.Cno=SC.Cno and Course.Tno=Teacher.Tno and Teacher.Tname='叶平');
14、查询和“1002”号的同窗学习的教程大同小异的其余同学学号和人名;
    select Sno from SC where Cno in (select Cno from SC where Sno='1002')
    group by Sno having count(*)=(select count(*) from SC where Sno='1002');
15、删除学习“叶平”老师课的SC表记录;
    Delect SC
    from course ,Teacher 
    where Course.Cno=SC.Cno and Course.Tno= Teacher.Tno and Tname='叶平';
16、向SC表中插入一些笔录,这个记录供给相符以下条件:未有上过编号“003”课程的校友学号、2、
    号课的平分战绩;
    Insert SC select Sno,'002',(Select avg(score)
    from SC where Cno='002') from Student where Sno not in (Select Sno from SC where Cno='002');
17、按平均战表从高到低展现全体学员的“数据库”、“公司管理”、“乌Crane语”三门的学科成绩,按如下格局展示: 学生ID,,数据库,公司管理,丹麦语,有效课程数,有效平均分
    SELECT Sno as 学生ID
        ,(SELECT score FROM SC WHERE SC.Sno=t.Sno AND Cno='004') AS 数据库
        ,(SELECT score FROM SC WHERE SC.Sno=t.Sno AND Cno='001') AS 公司处理
        ,(SELECT score FROM SC WHERE SC.Sno=t.Sno AND Cno='006') AS 英语
        ,COUNT(*) AS 有效课程数, AVG(t.score) AS 平均成绩
    FROM SC AS t
    GROUP BY Sno
    ORDER BY avg(t.score) 
18、查询各科成绩最高和最低的分:以如下情势显得:课程ID,最高分,最低分
    SELECT L.Cno As 课程ID,L.score AS 最高分,R.score AS 最低分
    FROM SC L ,SC AS R
    WHERE L.Cno = R.Cno and
        L.score = (SELECT MAX(IL.score)
                      FROM SC AS IL,Student AS IM
                      WHERE L.Cno = IL.Cno and IM.Sno=IL.Sno
                      GROUP BY IL.Cno)
        AND
        R.Score = (SELECT MIN(IR.score)
                      FROM SC AS IR
                      WHERE R.Cno = IR.Cno
                  GROUP BY IR.Cno
                    );
19、按各科平均成绩从低到高和及格率的比重从高到低依次
    SELECT t.Cno AS 课程号,max(course.Cname)AS 课程名,isnull(AVG(score),0) AS 平均成绩
        ,100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分数
    FROM SC T,Course
    where t.Cno=course.Cno
    GROUP BY t.Cno
    ORDER BY 100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC
20、查询如下课程平均战表和及格率的百分比(用"1行"展现): 企管(001),马克思(002),OO&UML (003),数据库(004)
    SELECT SUM(CASE WHEN Cno ='001' THEN score ELSE 0 END)/SUM(CASE Cno WHEN '001' THEN 1 ELSE 0 END) AS 集团管理平均分
        ,100 * SUM(CASE WHEN Cno = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN Cno = '001' THEN 1 ELSE 0 END) AS 集团管理及格百分数
        ,SUM(CASE WHEN Cno = '002' THEN score ELSE 0 END)/SUM(CASE Cno WHEN '002' THEN 1 ELSE 0 END) AS 马克思平均分
        ,100 * SUM(CASE WHEN Cno = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN Cno = '002' THEN 1 ELSE 0 END) AS 马克思及格百分数
        ,SUM(CASE WHEN Cno = '003' THEN score ELSE 0 END)/SUM(CASE Cno WHEN '003' THEN 1 ELSE 0 END) AS UML平均分
        ,100 * SUM(CASE WHEN Cno = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN Cno = '003' THEN 1 ELSE 0 END) AS UML及格百分数
        ,SUM(CASE WHEN Cno = '004' THEN score ELSE 0 END)/SUM(CASE Cno WHEN '004' THEN 1 ELSE 0 END) AS 数据库平均分
        ,100 * SUM(CASE WHEN Cno = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN Cno = '004' THEN 1 ELSE 0 END) AS 数据库及格百分数
  FROM SC
21、查询差异老师所教分化科目平均分从高到低突显
  SELECT max(Z.Tno) AS 教师ID,MAX(Z.Tname) AS 教授姓名,C.Cno AS 课程ID,MAX(C.Cname) AS 课程名称,AVG(Score) AS 平均战绩
    FROM SC AS T,Course AS C ,Teacher AS Z
    where T.Cno=C.Cno and C.Tno=Z.Tno
  GROUP BY C.Cno
  ORDER BY AVG(Score) DESC
22、查询如下课程战表第 3 名到第 6 名的学员战表单:集团管理(001),Marx(002),UML (003),数据库(004)
    [学生ID],[学员姓名],企管,马克思,UML,数据库,平均成绩
    SELECT  DISTINCT top 3
      SC.Sno As 学生学号,
        Student.Sname AS 学生姓名 ,
      T1.score AS 集团管理,
      T2.score AS 马克思,
      T3.score AS UML,
      T4.score AS 数据库,
      ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 总分
      FROM Student,SC  LEFT JOIN SC AS T1
                      ON SC.Sno = T1.Sno AND T1.Cno = '001'
            LEFT JOIN SC AS T2
                      ON SC.Sno = T2.Sno AND T2.Cno = '002'
            LEFT JOIN SC AS T3
                      ON SC.Sno = T3.Sno AND T3.Cno = '003'
            LEFT JOIN SC AS T4
                      ON SC.Sno = T4.Sno AND T4.Cno = '004'
      WHERE student.Sno=SC.Sno and
      ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
      NOT IN
      (SELECT
            DISTINCT
            TOP 15 WITH TIES
            ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0)

  • ISNULL(T4.score,0)
          FROM sc
                LEFT JOIN sc AS T1
                          ON sc.Sno = T1.Sno AND T1.Cno = 'k1'
                LEFT JOIN sc AS T2
                          ON sc.Sno = T2.Sno AND T2.Cno = 'k2'
                LEFT JOIN sc AS T3
                          ON sc.Sno = T3.Sno AND T3.Cno = 'k3'
                LEFT JOIN sc AS T4
                          ON sc.Sno = T4.Sno AND T4.Cno = 'k4'
          ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC);

23、总结列印各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[ <60]
    SELECT SC.Cno as 课程ID, Cname as 课程名称
        ,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85]
        ,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70]
        ,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60]
        ,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]
    FROM SC,Course
    where SC.Cno=Course.Cno
    GROUP BY SC.Cno,Cname;

24、查询学平生均战绩及其排行
      SELECT 1+(SELECT COUNT( distinct 平均战表)
              FROM (SELECT Sno,AVG(score) AS 平均成绩
                      FROM SC
                  GROUP BY Sno
                  ) AS T1
            WHERE 平均成绩 > T2.等分成绩) as 排行,
      Sno as 学生学号,平均战表
    FROM (SELECT Sno,AVG(score) 平均战绩
            FROM SC
        GROUP BY Sno
        ) AS T2
    O奥迪Q5DEENCORE BY 平均战绩 desc;
 
25、查询各科战绩前三名的记录:(不思量战表并列情状)
      SELECT t1.Sno as 学生ID,t1.Cno as 课程ID,Score as 分数
      FROM SC t1
      WHERE score IN (SELECT TOP 3 score
              FROM SC
              WHERE t1.Cno= Cno
            ORDER BY score DESC
              )
      ORDER BY t1.Cno;
26、查询每门科目被选修的学员数
  select Cno,count(Sno) from sc group by Cno;
27、查询出只选修了一门科目标整个学员的学号和人名
  select SC.Sno,Student.Sname,count(Cno) AS 选课数
  from SC ,Student
  where SC.Sno=Student.Sno group by SC.Sno ,Student.Sname having count(Cno)=1;
28、查询男子、女人人数
    Select count(Ssex) as 男士人数 from Student group by Ssex having Ssex='男';
    Select count(Ssex) as 女子人数 from Student group by Ssex having Ssex='女';
29、查询姓“张”的学生名单
    SELECT Sname FROM Student WHERE Sname like '张%';
30、查询同名同种性别学生名单,并总结同有名气的人数
  select Sname,count(*) from Student group by Sname having  count(*)>1;;
31、壹玖捌壹年诞生的学生名单(注:Student表中Sage列的种类是datetime)
    select Sname,  CONVERT(char (11),DATEPART(year,Sage)) as age
    from student
    where  CONVERT(char(11),DATEPART(year,Sage))='1981';
32、查询每门学科的平均成绩,结果按平均成绩升序排列,平均成绩一样时,按学科号降序排列
    Select Cno,Avg(score) from SC group by Cno order by Avg(score),Cno DESC ;
33、查询平均战表超越85的具有学生的学号、姓名和平均战表
    select Sname,SC.Sno ,avg(score)
    from Student,SC
    where Student.Sno=SC.Sno group by SC.Sno,Sname having    avg(score)>85;
34、查询课程名叫“数据库”,且分数低于60的上学的小孩子姓名和分数
    Select Sname,isnull(score,0)
    from Student,SC,Course
    where SC.Sno=Student.Sno and SC.Cno=Course.Cno and  Course.Cname='数据库'and score <60;
35、查询全部学员的选课景况;
    SELECT SC.Sno,SC.Cno,Sname,Cname
    FROM SC,Student,Course
    where SC.Sno=Student.Sno and SC.Cno=Course.Cno ;
36、查询其余一门科目战表在70分以上的全名、课程名称和分数;
    SELECT  distinct student.Sno,student.Sname,SC.Cno,SC.score
    FROM student,Sc
    WHERE SC.score>=70 AND SC.Sno=student.Sno;
37、查询比不上格的学科,并按学科号从大到小排列
    select Cno from sc where scor e <60 order by Cno ;
38、查询课程编号为003且课程成绩在80分以上的学员的学号和人名;
    select SC.Sno,Student.Sname from SC,Student where SC.Sno=Student.Sno and Score>80 and Cno='003';
39、求选了课程的学生人数
    select count(*) from sc;
40、查询选修“叶平”老师所授课程的学习者中,成绩最高的学生姓名及其成绩
    select Student.Sname,score
    from Student,SC,Course C,Teacher
    where Student.Sno=SC.Sno and SC.Cno=C.Cno and C.Tno=Teacher.Tno and Teacher.Tname='叶平' and SC.score=(select max(score)from SC where Cno=C.Cno );
41、查询各种科目及相应的选修人数
    select count(*) from sc group by Cno;
42、查询差别学科战绩同样的学习者的学号、课程号、学生战表
  select distinct  A.Sno,B.score from SC A  ,SC B where A.Score=B.Score and A.Cno <>B.Cno ;
43、查询每门功战表最佳的前两名
    SELECT t1.Sno as 学生ID,t1.Cno as 课程ID,Score as 分数
      FROM SC t1
      WHERE score IN (SELECT TOP 2 score
              FROM SC
              WHERE t1.Cno= Cno
            ORDER BY score DESC
              )
      ORDER BY t1.Cno;
44、总括每门课程的上学的小孩子选修人数(当先10人的教程才计算)。要求输出课程号和选修人数,查询结果按人头降序排列,查询结果按人口降序排列,若人数同样,按学科号升序排列 
    select  Cno as 课程号,count(*) as 人数
    from  sc 
    group  by  Cno
    order  by  count(*) desc,Cno 
45、检索最少选修两门课程的上学的小孩子学号
    select  Sno 
    from  sc 
    group  by  Sno
    having  count(*)  >  =  2
46、查询全数上学的儿童都选修的科目标课程号和学科名
    select  Cno,Cname 
    from  Course 
    where  Cno  in  (select  Cno  from  sc group  by  Cno) 
47、查询没学过“叶平”老师讲课的任一门学科的学员姓名
    select Sname from Student where Sno not in (select Sno from Course,Teacher,SC where Course.Tno=Teacher.Tno and SC.Cno=course.Cno and Tname='叶平');
48、查询两门以上不比格课程的校友的学号及其平均战绩
    select Sno,avg(isnull(score,0)) from SC where Sno in (select Sno from SC where score <60 group by Sno having count(*)>2)group by Sno;
49、检索“004”课程分数小于60,按分数降序排列的同学学号
    select Sno from SC where Cno='004'and score <60 order by score desc;

 

SQL二〇〇九无法附加数据库,提示“无法展现诉求的对话框”(nColIndex实际值是-1)图像和文字化解办法

初稿地址:http://www.maomao365.com/?p=7335

消除办法:使用EXECUTE AS语句修改施行权限。代码如下:

运用此命令首先保障您的mysql运转条件已经搭建好

SQL二〇一〇不可能附加数据库,提示“不能显示央浼的对话框”(nColIndex实际值是-1)图像和文字消除措施 

 

ALTER PROCEDURE [dbo].[sp_TruncateTable] 
    @TableName varchar(200) 
    WITH EXECUTE AS SELF
AS 
BEGIN 
    --打印出当前执行上下文用户
    SELECT  nt_username, loginame 
    FROM sys.sysprocesses 
    WHERE spid = @@SPID

    SET NOCOUNT ON; 
    DECLARE @TruncateSql nvarchar(2000);
    SET @TruncateSql = 'TRUNCATE TABLE ' + @TableName 
    EXEC (@TruncateSql) 
END

那是顾客端连接mysql服务器的下令,相比较全的写法是上边二种

 

摘要:

 

首先个是全拼,第三个是首先个的缩写

 

 

因而打字与印刷出来的loginame能够观察,施行顾客消息已经被更动。

mysql --host=localhost --user=myname --password=password利用sql脚本检查测验数据表中一列数据是还是不是三番五次的法子分享,SQL二〇〇九非常小概附加数据库。 mydb

明天,笔者在工作室换了一台微型Computer写Code,当本人在增大数据库的时候,出现如下极度,折腾了半天,照旧要命。于是本身就重装SQL,重装之后仍然不行。纠缠了,那时候作者也记不清去google,傻傻的就把系统重装了(新机)。折腾差不离一天之后,系统、SQL、VS二〇〇九、补丁等等全都解决之后,总算“马到功成了”,这年,笔者又跑去附加数据库。那回蛋疼了~~照旧是没戏。于是乎,有了那篇小说(好记性比不上烂笔头):

   数据表中,有一列是自行流水号,由于各个操作十分原因(大概插入失利),此列数据会变的不总是,下文将汇报使用sql脚本的方式获取数据表中的数目是或不是延续的方法共享,如下所示:

mysql -h localhost -u myname -ppassword mydb

 

 

貌似在行使中,大家会简单-h参数,mysql会自动默觉稳当地连接

出现错误 

   实验蒙受:sqlserver 二零零六 ENCORE2  

再有某个正是逐条参数之间是不是有空格的主题素材,-u后边能够有也得以大约空格,对于-p前边的参数小编要独立说一下

 


那是本人从mysql官方文书档案拷过来的从头到尾的经过

 

 

for password options, the password value is optional:

 图片 1

例:获取表test中keyId是还是不是为连日来的数目

  If you use a -p or --password option and specify the password value, there must be no space between -p or --password= and the password following it.

 

 

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